Answer
$2$
Work Step by Step
$\lim\limits_{(x,y) \to (1,1)} \dfrac{(x-y)(x+y)}{x-y}=\lim\limits_{(x,y) \to (1,1)}(x+y)$
Thus, we have $\lim\limits_{(x,y) \to (1,1)} \dfrac{(x-y)(x+y)}{x-y}=1+1=2$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 14: Partial Derivatives - Section 14.2 - Limits and Continuity in Higher Dimensions - Exercises 14.2 - Page 796: 14
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