Answer
$0$
Work Step by Step
Here, $\lim\limits_{(x,y) \to (1,1)} \dfrac{(x-y)^2}{x-y}=\lim\limits_{(x,y) \to (1,1)}(x-y)$
Thus, $\lim\limits_{(x,y) \to (1,1)} \dfrac{(x-y)^2}{x-y}=1-1=0$
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