Answer
$0$
Work Step by Step
Here, $\lim\limits_{(x,y) \to (1,1)} \dfrac{(x-y)^2}{x-y}=\lim\limits_{(x,y) \to (1,1)}(x-y)$
Thus, $\lim\limits_{(x,y) \to (1,1)} \dfrac{(x-y)^2}{x-y}=1-1=0$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 14: Partial Derivatives - Section 14.2 - Limits and Continuity in Higher Dimensions - Exercises 14.2 - Page 796: 13
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
