Answer
$\dfrac{4}{5}$
Work Step by Step
Consider the series $\dfrac{1}{1+x}=1-x+x^2-x^3+....+(-x)^n$
As we are given that $x=\dfrac{1}{4}$
Then, the sum of the series is as follows:
$\dfrac{1}{1+x}=\dfrac{1}{1+(\dfrac{1}{4})}=\dfrac{4}{(4+1)}=\dfrac{4}{5}$
