Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 10: Infinite Sequences and Series - Practice Exercises - Page 636: 29

Answer

conditionally convergent.

Work Step by Step

The alternating series test states that if the following conditions are met then the series is convergent. 1. $\lim\limits_{ n\to \infty} b_n=0$ 2.$b_n$ is a decreasing sequence. Consider $a_n=\Sigma_{n=1}^{\infty}\dfrac{(-1)^n}{ \ln(n+1)}$ From the given problem, we get $b_n=\dfrac{1}{\ln (n+1)}$ 1. $\lim\limits_{ n\to \infty} b_n=\lim\limits_{ n\to \infty} \dfrac{1}{\ln (n+1)}=0$ 2.$b_n=\dfrac{1}{\ln (n+1)}$ is a decreasing sequence. Therefore, the given series is conditionally convergent.
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