Answer
Divergent
Work Step by Step
$\Sigma^{\infty}_{n=1} \frac{1}{1+(\frac{2}{3})^{n}}$
$\lim\limits_{n \to \infty}a_{n} = \lim\limits_{n \to \infty}\frac{1}{1+(\frac{2}{3})^{n}}$
$=\frac{1}{1+0}$
$=1 \ne 0$
Since $\lim\limits_{n \to \infty}a_{n} \ne 0$, the series is divergent.