Answer
Diverges
Work Step by Step
$\lim _{n\rightarrow \infty }\dfrac {1}{4+e^{-n}}=\dfrac {1}{4+0}=\dfrac {1}{4}\neq 0\Rightarrow \sum ^{\infty }_{n=1}\dfrac {1}{4+e^{-n}}$. Diverges
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 11 - Section 11.2 - Series - 11.2 Exercises - Page 716: 33
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