Answer
Diverges
Work Step by Step
$\lim _{k\rightarrow \infty }\dfrac {k^{2}}{k^{2}-2k+5}=\lim _{k\rightarrow \infty }\dfrac {1}{1-\dfrac {2}{k}+\dfrac {5}{k^{2}}}=1\neq 0\Rightarrow \sum ^{\infty }_{k=1}\dfrac {k^{2}}{k^{2}-2k+5}$
Diverges
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 11 - Section 11.2 - Series - 11.2 Exercises - Page 716: 30
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