Chapter 10 - Review - Exercises - Page 690: 4

$\frac{x^2}{4}+(y-1)^2=1$

$x=2cos\theta$ $y=1+sin\theta$ $cos^2\theta=\frac{x^2}{4}$ $sin^2\theta =(y-1)^2$ Therefore, $cos^2\theta+sin^2\theta=\frac{x^2}{4}+(y-1)^2$ $\frac{x^2}{4}+(y-1)^2=1$ Also see attached graph