Answer
$=18$
Work Step by Step
Given: $r^2=9 cos 5 \theta$
$Area,A=\int_{- \pi/10}^{\pi/10}\frac{r^2}{2}d\theta$
$=\int_{- \pi/10}^{\pi/10}\dfrac{9cos5 \theta}{2}d\theta$
$=10[\dfrac{9sin5 \theta}{10}]_{- \pi/10}^{\pi/10}$
$=18$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 10 - Review - Exercises - Page 690: 31
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