Answer
$\dfrac{81}{20}$
Work Step by Step
$Area,A=\int_{t=-2}^{t=1}ydx$
and $dx=3t^2-3dt$
$A=3\int_{-2}^{1}(t^2+t+1)(t^2-1)dt$
$A=3[\frac{1}{5}t^5+\frac{1}{4}t^4-\frac{1}{2}t^2-t]_{-2}^{1}$
$A=\dfrac{81}{20}$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 10 - Review - Exercises - Page 690: 28
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