Answer
$y=\sqrt {x-1}$
Work Step by Step
$x=1+y^2=y=\pm\sqrt {x-1}$
However since $y\gt 0$
Therefore,
$y=\sqrt {x-1}$
Also see attached graph.
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 10 - Review - Exercises - Page 690: 2
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