Answer
$$e^{x}-\frac{1}{3}e^{3x}+c.$$
Work Step by Step
Since $(e^{3x})'=3e^{3x}$, then we have
$$
\int\frac{e^{2x}-e^{4x}}{e^{x}} d x=\int e^{x}-e^{3x}d x \\
=e^{x}-\frac{1}{3}e^{3x}+c.
$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.8 Inverse Trigonometric Functions - Exercises - Page 375: 89
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
