Answer
$$\frac{1}{2}e^{y^2}+c. $$
Work Step by Step
Let $u=y^2$, then $du=2ydy$. Now, we have
$$\int ye^{y^2}dy=\frac{1}{2}\int e^udu=\frac{1}{2}e^u+c=\frac{1}{2}e^{y^2}+c. $$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.8 Inverse Trigonometric Functions - Exercises - Page 375: 73
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