Answer
$$\frac{x^3}{3}-\frac{x^{-3}}{3}-2\ln x+c .$$
Work Step by Step
We have
$$\int (x-x^{-2})^2dx=\int x^2 +x^{-4}-2x^{-1}dx\\
=\frac{x^3}{3}-\frac{x^{-3}}{3}-2\ln x+c .$$
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