Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.8 Inverse Trigonometric Functions - Exercises - Page 375: 76

Answer

$$\frac{x^3}{3}-\frac{x^{-3}}{3}-2\ln x+c .$$

Work Step by Step

We have $$\int (x-x^{-2})^2dx=\int x^2 +x^{-4}-2x^{-1}dx\\ =\frac{x^3}{3}-\frac{x^{-3}}{3}-2\ln x+c .$$
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