Answer
$$-\frac{1}{12} e^{9-12t}+c.
$$
Work Step by Step
We have
$$\int e^{9-12t} dt=e^9\int e^{-12t}dt=\frac{e^9}{-12} e^{-12t}+c\\
=-\frac{1}{12} e^{9-12t}+c.
$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.8 Inverse Trigonometric Functions - Exercises - Page 375: 78
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