Answer
$$-e^{-x}-2x^2+c.$$
Work Step by Step
Since $(e^{-x})'=-e^{-x}$, then we have
$$
\int\left(e^{-x}-4 x\right) d x=-e^{-x}-2x^2+c.
$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.8 Inverse Trigonometric Functions - Exercises - Page 375: 87
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