Answer
$$x=±e$$
Work Step by Step
$\ln{x^4}-\ln{x^2}=2$
Since $\log{a}-\log{b}=\log{\frac{a}{b}}$,
$\ln\frac{x^4}{x^2}=2$
Thus,
$\ln{x^2}=2$
Raising $e$ to the power of both sides:
$x^2=e^2$
Solving for $x$:
$x=±e$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.3 Logarithms and Their Derivatives - Exercises - Page 342: 23
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
