Answer
$$5$$
Work Step by Step
$\log_2 {\frac{4}{3}}+\log_2 {24}$
$=\log_2 ({\frac{4}{3}\times {24}})$ {Since $\log{a}+\log{b}=\log{ab}$}
$=\log_2{32}=\log_2{2^5}=5$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.3 Logarithms and Their Derivatives - Exercises - Page 342: 14
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