Answer
$$1$$
Work Step by Step
$\log_4{48}-\log_4{12}$
$=\log_4{\frac{48}{12}}$ {Since $\log{a}-\log{b}=\log{\frac{a}{b}}$}
$=\log_4{4}=1$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.3 Logarithms and Their Derivatives - Exercises - Page 342: 11
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