Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.3 Logarithms and Their Derivatives - Exercises - Page 342: 12

Answer

$$\frac{19}{10}$$

Work Step by Step

$\ln({\sqrt{e}}\times e^{7/5})$ $=\ln{e^{1/2}}+\ln{e^{7/5}}$ {Since $\log{ab}=\log{a}+\log{b}$} $=\frac{1}{2}+\frac{7}{5} = \frac{5}{10}+\frac{14}{10}=\frac{19}{10}$
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