Answer
$$ f''(x)= 16 e^{4x-3}.$$
Work Step by Step
Recall that $(e^x)'=e^x$
Since we have
$$ f(x)= e^{4x-3}$$
then the first derivative $ f'(x)$, using the chain rule, is given by
$$ f'(x)= e^{4x-3}(4x-3)'=4 e^{4x-3}.$$
The second derivative $ f''(x)$ is given by
$$ f''(x)= 4 e^{4x-3}(4x-3)'=16 e^{4x-3}.$$
