Answer
$$ y=4x+4.$$
Work Step by Step
We have
$$ y'=4e^x\Longrightarrow y'(0)=4.$$
Then the slope of the tangent line at $ x=0$ is $ m= 4$. Hence the equation of the tangent line is given by
$$ y=mx+c=4x+c.$$
Since $ y(0)=4$, then $ c=4$, hence the tangent line at $ x=0$ is given by
$$ y=4x+4.$$