Answer
$G(1)$ = $0$
$G'(0)$ = $0$
$G'(\frac{\pi}{4})$ = $1$
Work Step by Step
$G(1)$ = $\int_1^1tan(t)dt$ = $0$
$G'(0)$ = $tan(0)$ = $0$
$G'(\frac{\pi}{4})$ = $tan(\frac{\pi}{4})$ = $1$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.5 The Fundamental Theorem of Calculus, Part II - Exercises - Page 262: 5
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