Answer
$F(0)$ = $0$
$F'(0)$ = $0$
$F'(3)$ = $\sqrt {12}$
Work Step by Step
$F(0)$ = $\int_0^0\sqrt{t^{2}+t}dt$ = $0$
$F'(0)$ = $\sqrt{0^{2}+0}$ = $0$
$F'(3)$ = $\sqrt{3^{2}+3}$ = $\sqrt {12}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.5 The Fundamental Theorem of Calculus, Part II - Exercises - Page 262: 4
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