Answer
$$ \sec (5 t-9) .$$
Work Step by Step
By making use of Theorem 1 (FTC II), we have
$$
\frac{d}{d t} \int_{100}^{t} \sec (5 x-9) d x=\sec (5 t-9) .
$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.5 The Fundamental Theorem of Calculus, Part II - Exercises - Page 262: 23
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