Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.5 The Fundamental Theorem of Calculus, Part II - Exercises - Page 262: 16

Answer

$$f(x)= \tan x+\tan (2x). $$

Work Step by Step

We have $$f(x)=\int_{-2 x}^{x} \sec^2tdt=\tan t|_{-2 x}^{x} \\ = \tan x+\tan (2x). $$
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