Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.5 The Fundamental Theorem of Calculus, Part II - Exercises - Page 262: 10

Answer

$f(x)=\tan x+1. $

Work Step by Step

We have $$ f(x)=\int_{-\pi/4}^x\sec^2\theta d\theta =\tan \theta |_{-\pi/4}^x=\tan x+1. $$
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