Answer
$f(x)= -\frac{1}{\sqrt x}+\frac{1}{2}$
Work Step by Step
We have
$$f(x)=\int_{2}^{\sqrt x}t^{-2}dt =-t^{-1}|_{2}^{\sqrt x}
\\=-\frac{1}{\sqrt x}+\frac{1}{2}
$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.5 The Fundamental Theorem of Calculus, Part II - Exercises - Page 262: 11
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