Answer
$128$
Work Step by Step
We have
$$\int_{0}^{2}\left(12 x^5+3x^2-4 x\right) d x=\frac{12x^6}{6}+\frac{3x^3}{3}-\frac{4x^2}{2}|_0^2\\
=128+8-8=128.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 257: 9
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