Answer
$A=\frac{4}{3}$
Work Step by Step
$f(x)=2x-x^2$
$Area=\int_0^2(2x-x^2)dx$
$A=[x^2-\frac{x^3}{3}]_0^2$
$A=4-\frac{8}{3}$
$A=\frac{4}{3}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 257: 2
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