Answer
$\frac{1}{2}$
Work Step by Step
$A$ = $\int_1^2x^{-2}dx$ = $\frac{x^{-1}}{-1}|_1^2$ = $-\frac{1}{x}|_1^2$ = $-\frac{1}{2}-(-1)$ = $\frac{1}{2}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 257: 3
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