Answer
$$\frac{381}{7}.$$
Work Step by Step
We have
$$\int_{1}^{8} x^{4/3}dx=\frac{1}{7/3}x^{7/3}|_{1}^8=\frac{3}{7}8^{7/3}-\frac{3}{7}\\=\frac{3(2^7)}{7} -\frac{3}{7}=\frac{381}{7}.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 257: 14
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