Answer
$-1$
Work Step by Step
We have
$$\int_{0}^{1}\left(4 x-9 x^{2}\right) d x=\frac{4x^2}{2}-\frac{9x^3}{3}|_0^1\\
=2-3=-1.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 257: 7
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