Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.4 The Fundamental Theorem of Calculus, Part I - Exercises - Page 257: 4

Answer

$1$

Work Step by Step

$A$ = $\int_0^\frac{\pi}{2}cosxdx$ = $sinx |_0^\frac{\pi}{2}$ = $sin\frac{\pi}{2}-sin0$ = $1$
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