Answer
$$\frac{4}{5}$$
Work Step by Step
Since
$$\int_{1}^{b} f(x) d x =1-b^{-1} $$
Then
\begin{aligned}
\int_{1}^{5} f(x) d x &=1-5^{-1} \\
&=1-\frac{1}{5} \\
&=\frac{4}{5}
\end{aligned}
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.2 The Definite Integral - Exercises - Page 246: 63
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