Answer
$\int_{5}^{9} f(x) d x.$
Work Step by Step
We have
$$
\int_{2}^{9} f(x) d x-\int_{2}^{5} f(x) d x\\
=-\int_{9}^{2} f(x) d x-\int_{2}^{5} f(x) d x\\
=-\int_{9}^{5} f(x) d x=\int_{5}^{9} f(x) d x.
$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.2 The Definite Integral - Exercises - Page 246: 61
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