Answer
4
Work Step by Step
$\int^{1}_{0}f(x)dx+\int^{4}_{1}f(x)dx=\int^{2}_{0}f(x)dx+\int^{4}_{2}f(x)dx $
$\implies \int^{4}_{2}f(x)dx=\int^{1}_{0}f(x)dx+\int^{4}_{1}f(x)dx-\int^{2}_{0}f(x)dx $
$=1+7-4=4$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 5 - The Integral - 5.2 The Definite Integral - Exercises - Page 246: 58
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