Answer
$$ y'= 12\sin(2-3x).$$
Work Step by Step
Recall that $(\cos x)'=-\sin x$.
Since $ y=4\cos(2-3x)$, then by the chain rule, the derivative $ y'$ is given by
$$ y'=-4\sin(2-3x) (-3)=12\sin(2-3x).$$
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