Answer
$$ y'= -6x^{-\frac{5}{2}}.$$
Work Step by Step
Recall that $(x^n)'=nx^{n-1}$
Since $ y=4x^{-3/2}$, then the derivative $ y'$ is given by
$$ y'=4(-3/2)x^{-(3/2)-1}=-6x^{-\frac{5}{2}}.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - Chapter Review Exercises - Page 163: 28
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