Answer
$$ y'= 6(4x^3-9) (x^4-9x)^5 .$$
Work Step by Step
Recall that $(x^n)'=nx^{n-1}$
Since $ y=(x^4-9x)^6$, then by the chain rule the derivative $ y'$ is given by
$$ y'=6 (x^4-9x)^5(4x^3-9)=6(4x^3-9 )(x^4-9x)^5 .$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - Chapter Review Exercises - Page 163: 33
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
