Answer
$$ y'=15 x^4-14x.$$
Work Step by Step
Recall that $(x^n)'=nx^{n-1}$
Since $ y=3x^5-7x^2+4$, then the derivative $ y'$ is given by
$$ y'=3\times5x^{5-1}-2\times7x^{2-1}+0$$
$$=15 x^4-14x$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - Chapter Review Exercises - Page 163: 27
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