Answer
$$ y'= 8x+2x^{-3}.$$
Work Step by Step
Recall that $(x^n)'=nx^{n-1}$
Since $ y=4x^2-x^{-2}$, then the derivative $ y'$ is given by
$$ y'= 4(2)x- (-2)x^{-2-1}=8x+2x^{-3}.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - Chapter Review Exercises - Page 163: 30
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