Answer
$$ y'= -7.3t^{-8.3}.$$
Work Step by Step
Recall that $(x^n)'=nx^{n-1}$
Since $ y=t^{-7.3}$, then the derivative $ y'$ is given by
$$ y'= -7.3 t^{-7.3-1}=-7.3t^{-8.3}.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - Chapter Review Exercises - Page 163: 29
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