Answer
$-\frac{1}{4}$.
Work Step by Step
Since $ f(t)=\frac{t}{t+1}$, then we get
$$ f'(t)=\frac{(t+1)-t}{(t+1)^2}=\frac{1}{(t+1)^2}, \quad f''(t)=-\frac{2}{(t+1)^3}.$$
Hence, $ f''(1)=-\frac{2}{(1+1)^3}=-\frac{1}{4}$.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - 3.5 Higher Derivatives - Exercises - Page 135: 24
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
