Answer
$1$
Work Step by Step
\begin{align*}
\lim _{x \rightarrow 0} \frac{\sin x\sec x}{x}&=\lim _{x \rightarrow 0} \frac{\sin x}{x}\sec x\\
&=\lim _{x \rightarrow 0} \frac{\sin x}{x}\lim _{x \rightarrow 0}\sec x\\
&=1.
\end{align*}
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