Answer
$$1$$
Work Step by Step
\begin{align*}
\lim _{x \rightarrow 0} \frac{\tan x}{x}&=\lim _{x \rightarrow 0} \frac{\sin x}{x}\frac{1}{\cos x}\\
&=\lim _{x \rightarrow 0} \frac{\sin x}{x}\lim _{x \rightarrow 0}\frac{1}{\cos x}\\
&=1.
\end{align*}