Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 15 - Differentiation in Several Variables - 15.3 Partial Derivatives - Exercises - Page 781: 42

Answer

$$ f_y(0,\pi)= 1 $$

Work Step by Step

Since $ f(x,y)=\sin(x^2-y)$, then we have $$ f_y=-\cos(x^2-y).$$ Hence, we get $$ f_y(0,\pi)= -\cos (-\pi)=1 $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.