Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 15 - Differentiation in Several Variables - 15.3 Partial Derivatives - Exercises - Page 781: 13

Answer

$\frac{dz}{dx} = 2x$ $\frac{dz}{dx} = 2y$

Work Step by Step

$\frac{dz}{dx} = \frac{d}{dx}(x^2) + \frac{d}{dx}(y^2)$ Because we're differentiating in terms of x, $y^2$ would be counted as a constant: $\frac{dz}{dx} = 2x$ $\frac{dz}{dy} = \frac{d}{dy}(x^2) + \frac{d}{dy}(y^2)$ Because we're differentiating in terms of y, $x^2$ would be counted as a constant: $\frac{dz}{dx} = 2y$
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