Answer
$$ f_x(1,2)= -164$$
Work Step by Step
Since $ f(x,y)=3x^2y+4x^3y^2-7xy^5$, then we have
$$ f_x=6xy+12x^2y^2-7y^5.$$
Hence, we get
$$ f_x(1,2)=6(2)+12(4)-7(2^5)=-164$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 15 - Differentiation in Several Variables - 15.3 Partial Derivatives - Exercises - Page 781: 41
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