Answer
$$ V_r=2\pi rh,\quad V_h=\pi r^2.$$
Work Step by Step
Recall that $(x^n)'=nx^{n-1}$
Since $ V=\pi r^2h $, then we have
$$ V_r=2\pi rh,\quad V_h=\pi r^2.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 15 - Differentiation in Several Variables - 15.3 Partial Derivatives - Exercises - Page 781: 16
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